1/x^2-4x+4=2/x^2+4x-8

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Solution for 1/x^2-4x+4=2/x^2+4x-8 equation: 



1/x^2-4x+4=2/x^2+4x-8

We move all terms to the left:

1/x^2-4x+4-(2/x^2+4x-8)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x^2+4x-8)!=0

x∈R



We add all the numbers together, and all the variables

-4x+1/x^2-(2/x^2+4x-8)+4=0

We get rid of parentheses

-4x+1/x^2-2/x^2-4x+8+4=0

We multiply all the terms by the denominator


-4x*x^2-4x*x^2+8*x^2+4*x^2+1-2=0

We add all the numbers together, and all the variables

12x^2-4x*x^2-4x*x^2-1=0

Wy multiply elements

12x^2-4x^3-4x^3-1=0

We do not support expression: x^3

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